A and B together, B and C together and A and C together

Solution

Let, the total work be 396 units (LCM of 44, 33 and 36) Amount of work done by A and B together in one day = 396/44 = 9 units Amount of work done by B and C together in one day = 396/33 = 12 units Amount of work done by A and C together in one day = 396/36 = 11 units Amount of work done by A, B and C together in one day = (9 + 12 + 11)/2 = 16 units Amount of work done by A alone in one day = 16 – 12 = 4 units Amount of work done by B alone in one day = 16 – 11 = 5 units Amount of work done by C alone in one day = 16 – 9 = 7 units So the desired ratio = 4:5:7