Question
βAβ and βBβ can do a piece of work in 10 days
and 20 days, respectively. They started working together but βAβ left after 3 days. Find the time taken by βBβ to complete the remaining work.Solution
Let total amount of work be 20 units (LCM of 10 and 20). Efficiency of βAβ = 20/10 = 2 units/day Efficiency of βBβ = 20/20 = 1 units/day Amount of work done by βAβ and βBβ together in 3 days = (2 + 1) Γ 3 = 9 units Time taken by B to complete remaining work = {(20 β 9)/1} = 11 days
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