Let total amount of work be 60 units (LCM of 12 and 20). Efficiency of ‘A’ = 60/12 = 5 units/day Efficiency of ‘B’ = 60/20 = 3 units/day Amount of work done by ‘A’ and ‘B’ together in 6 days = (5 + 3) × 6 = 48 units Time taken by B to complete remaining work = {(60 – 48)/3} = 4 days
Total mechanical energy =
The shape of our Milky Way galaxy is
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