Question
βAβ and βBβ can do a piece of work in 12 days
and 20 days, respectively. They started working together but βAβ left after 6 days. Find the time taken by βBβ to complete the remaining work.Solution
Let total amount of work be 60 units (LCM of 12 and 20). Efficiency of βAβ = 60/12 = 5 units/day Efficiency of βBβ = 60/20 = 3 units/day Amount of work done by βAβ and βBβ together in 6 days = (5 + 3) Γ 6 = 48 units Time taken by B to complete remaining work = {(60 β 48)/3} = 4 days
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