Question
βAβ and βBβ can do a piece of work in 20 days
and 25 days, respectively. They started working together but βAβ left after 4 days. Find the time taken by βBβ to complete the remaining work.Solution
Let total amount of work be 100 units (LCM of 20 and 25). Efficiency of βAβ = 100/20 = 5 units/day Efficiency of βBβ = 100/25 = 4 units/day Amount of work done by βAβ and βBβ together in 4 days = (5 + 4) Γ 4 = 36 units Time taken by B to complete remaining work = {(100 β 36)/4} = 16 days
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