Question
βAβ and βBβ can do a piece of work in 15 days
and 20 days, respectively. They started working together but βAβ left after 3 days. Find the time taken by βBβ to complete the remaining work.Solution
Let total amount of work be 60 units (LCM of 15 and 20). Efficiency of βAβ = 60/15 = 4 units/day Efficiency of βBβ = 60/20 = 3 units/day Amount of work done by βAβ and βBβ together in 3 days = (4 + 3) Γ 3 = 21 units Time taken by B to complete remaining work = {(60 β 21)/3} = 13 days
?% of 1499.89 + 54.14 Γ 8 = 25.05% of 5568.08
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.87% of 79.98 + 19.69% of 64.22) Γ 4.83 = ?
? + 163.99 β 108.01 = 25.01 Γ 6.98
80.09 * β144.05+ ? * β224.87 = (2109.09 Γ· β1368.79) * 19.89
(15.15Β Γ Β 31.98) + 30.15% of 719.99 = ? + 124.34
(124.99)Β² = ?
6.992 + (2.01 Γ 2.98) + ? = 175.03
(627.98 Γ· 3.98 + 11.01 X 12.98 - ?) Γ· β623 = (178.98 + 37.08) Γ· 23.98Β