Question
βAβ and βBβ can do a piece of work in 15 days
and 20 days, respectively. They started working together but βAβ left after 3 days. Find the time taken by βBβ to complete the remaining work.Solution
Let total amount of work be 60 units (LCM of 15 and 20). Efficiency of βAβ = 60/15 = 4 units/day Efficiency of βBβ = 60/20 = 3 units/day Amount of work done by βAβ and βBβ together in 3 days = (4 + 3) Γ 3 = 21 units Time taken by B to complete remaining work = {(60 β 21)/3} = 13 days
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
28.95% of 924.78 + 1955% of 38.99 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
9.99% of 19.86% of 30.23% of (11999.84 Γ 9.68) = ?
29.98% of 549.99 = ? - 254.97 + 79.98% of 74.99Β
1131.98 + ? β 1125.04 = 1364.93 β 1168.01
98.999 x 99.001 + 640.856=?
What approximate value should come in the place of (?) in the following questions?
?3 -18.32 * 40.24 Γ· β399 = 200.79Β + 105.78
...960.02 of 238.89 Γ· 144.01 of 79.97 = ?