Question
βAβ alone can complete a work in 17 days. βBβ
alone can complete the same work in 34 days. If βAβ and βBβ work together for 5 days, then the remaining work can be completed by βAβ alone in how many days?Solution
Let the total amount of work = 34 units {LCM of 17 and 34} Then, efficiency of βAβ = 34/17 = 2 units/day Efficiency of βBβ = 34/17 = 1 units/day Combined efficiency of βAβ and βBβ = 2 + 1 = 3 units/day Work completed by βAβ and βBβ together in 5 days = 3 Γ 5 = 15 units Remaining work = 34 β 15 = 19 units Time taken by βAβ alone to complete the remaining work = 19/2 = 9.5 days
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