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    Question

    β€˜A’ is 25% less efficient than β€˜B’, and β€˜C’

    is 75% more efficient than β€˜B’. All three together complete a task in 32 days. After β€˜A’ and β€˜B’ work together for 16 days, they stop. How long will β€˜C’ take to finish the remaining work?
    A 24 days Correct Answer Incorrect Answer
    B 16 days Correct Answer Incorrect Answer
    C 20 days Correct Answer Incorrect Answer
    D 18 days Correct Answer Incorrect Answer
    E 48 days Correct Answer Incorrect Answer

    Solution

    Let efficiency of β€˜B’ = x units/day
    Efficiency of β€˜A’ = 0.75x units/day
    Efficiency of β€˜C’ = 1.75x units/day Total work = (x + 0.75x + 1.75x) Γ— 32 = 3.5x Γ— 32 = 112x units Work done by β€˜A’ and β€˜B’ in 16 days = (x + 0.75x) Γ— 16 = 1.75x Γ— 16 = 28x units Remaining work = 112x – 28x = 84x units Time required by β€˜C’ = 84x / 1.75x = 48 days

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