Question
βAβ and βBβ can do a piece of work in 30 days
and 20 days, respectively. If they started the work together and worked on it for 4 days, then find the time taken by βBβ alone to complete the remaining work.Solution
Let total amount of work be 60 unitsΒ Efficiency of βAβ = 60/30 = 2 units/day Efficiency of βBβ = 60/20 = 3 units/day Amount of work done by βAβ and βBβ together in 4 days = (2 + 3) Γ 4 = 20 units Time taken by B to complete remaining work = (60 β 20)/3 = 40/3 days
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