Question
βAβ and βBβ can do a piece of work in 12 days
and 15 days, respectively. If they started the work together and worked on it for 2 days, then find the time taken by βBβ alone to complete the remaining work.Solution
Let total amount of work be 60 unitsΒ Efficiency of βAβ = 60/12 = 5 units/day Efficiency of βBβ = 60/15 = 4 units/day Amount of work done by βAβ and βBβ together in 2 days = (5 + 4) Γ 2 = 18 units Time taken by B to complete remaining work = (60 β 18)/4 = 10.5 days
The preparation of a trial balance is for:
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