Question
A buffalo alone can plough field ‘A’ in 30 days. A
Bull alone can plough the field ‘A’ in 50 days. Find the number of days taken by 2 bulls and 1 buffalo to together plough field ‘B’ that is 10% larger than field ‘A’?Solution
Let the total work done to plough field ‘A’ = 150 units (LCM of 30 and 50) Then, efficiency of a buffalo = (150/30) = 5 units/day Efficiency of a bull = (150/50) = 3 units/day Total work required to plough field ‘B’ = 150 × 1.1 = 165 units Combined efficiency of 2 bulls and a buffalo = 3 × 2 + 5 = 11 units So, number of days required to plough field ‘B’ = 165/11 = 15 days
What is the position of P with respect to her sister?
Six persons are sitting in two straight rows, facing north. Their names are A, B, C, D, E and F. A and F are sitting at diagonally opposite ends. B is i...
Which of the following statement is not true before the final arrangement?
Which of the following statements is definitely false?
Six friends are sitting in a straight line. E is 4th from the right. E is between B and D. A is adjacent to B. D is adjacent to C. D is between E and C....
Five friends, D, E, F, G and H, are sitting in a straight line. D and E are adjacent to each other. E is between D and F. D is third to the left of G. G...
Who among the following person sits fourth to the left of G?
What is the position of F with respect to H?
Who among the following person sits opposite to H?
X has tuition centre in which place?
Relevant for Exams:
