Question
A buffalo alone can plough field ‘A’ in 40 days. A
Bull alone can plough the field ‘A’ in 80 days. Find the number of days taken by 3 bulls and 1 buffalo to together plough field ‘B’ that is 25% larger than field ‘A’?Solution
Let the total work done to plough field ‘A’ = 80 units (LCM of 40 and 80) Then, efficiency of a buffalo = (80/40) = 2 units/day Efficiency of a bull = (80/80) = 1 units/day Total work required to plough field ‘B’ = 80 × 1.25 = 100 units Combined efficiency of 3 bulls and 1 buffalo = 1 × 3 + 2 × 1 = 5 units So, number of days required to plough field ‘B’ = 100/5 = 20 days
5 6 14 45 ? 925
...16, 24, ?, 64, 104, 168, 272
What will come in place of the question mark (?) in the following series?
22, 25, 30, 37, 48, ?
Find the missing number in the given number series.
6, 15, 35, 66, 108, ?124, 107, 91, ? , 62, 49
23Â Â Â Â 40Â Â Â Â Â Â 67 Â Â Â Â Â Â 104Â Â Â Â Â Â ? Â Â Â Â Â Â 208
...12, 25, 51, ?, 207, 415Â
24, 8, 15, ?, 12, 4
2.5, 5, 15, 60, ?, 1800, 12600Â
Which of the following number will replace the question mark (?) and complete the given number series?
4, 5, 12, 39, 160, ?
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