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Let total work = 60 units (LCM of 15 and 20) Efficiency of ‘A’ = (60/15) = 4 units/day Efficiency of ‘B’ = (60/20) = 3 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (60/4) = 15 units/day Efficiency of ‘C’ = 15 – (4 + 3) = 8 units/day Required time taken = (60/8) = 7.5 days
Statement: G ≤ L ≥ O ≥ W ≥ I < N
Conclusion: I. I < L II. L = I
...Which among the following symbols should replace the question mark [?] (in the same order from left to right) in the given expression in order to make b...
Statements: X @ Y $ Z & U, Z @ V
Conclusions: I. V # X II. V $ X
...Statements: A = B > H ≥ C = F ≥ D > E > G
Conclusions:
I. H < G
II. B > E
III. D ≤ A
Statement:
R ≤ P >K ≤ L; W ≤ X = K > O; Q > L
Conclusion:
I) W < L
II) L = W
Statements: T > V > Q > S; L > S > V ≥ O ≤ X < Y
Conclusions:
I. T > L
II. V ≥ Y
III. T > O
Statements: T @ A % S $ L © J
Conclusions:
I. T % L
II. T $ L
III. S # J
Statement:
Q < B ≥ M; M > T = V; S < J = K ≥ L; V > K
Conclusion:
I. B > S
II. B > L
III. M < J
Statements: C ≥ E > M ≤ Z < B; G ≥ Z > K
Conclusions: I. C > K II. G ≥ B �...
Statements:
A ≤ B > E ≥ F; M > E < N
Conclusions:
I. N > F
II. B > F