Question
A work can be completed by βAβ and βBβ, alone in
7 days and 14 days, respectively. Find the number of days taken by βCβ to complete the same work alone if βAβ, βBβ and βCβ together can complete the whole work in 4 days.Solution
Let total work = 14 units (LCM of 7 and 14) Efficiency of βAβ = (14/7) = 2 units/day Efficiency of βBβ = (14/14) = 1 units/day Combined efficiency of βAβ, βBβ and βCβ = (14/4) = 3.5 units/day Efficiency of βCβ = 3.5 β (2 + 1) = 0.5 units/day Required time taken = (14/0.5) = 28 days
Evaluate:
(24/6) + 3 Γ (5 - 2)2
- What will come in place of the question mark (?) in the following questions?
120Γ·(5Γ2)+8=? 15 * 12 + 35% of 80 + 70% of 130 = ?
672 ÷ 28 × 24 + 363 – 309 =?
14% of 700 + 15% of 900 + 10% of 160 = ?
((1024)n/5Β Γ (42n+1Β ))/(16nΒ Γ 4n-1Β ) = ?
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)35% of 240 β 6 2 = ? 2 β β256
- What will come in the place of question mark (?) in the given expression?
(40 Γ· 5 + 56 Γ· 8) X (? - 42) = 120