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Let total work = 14 units (LCM of 7 and 14) Efficiency of ‘A’ = (14/7) = 2 units/day Efficiency of ‘B’ = (14/14) = 1 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (14/4) = 3.5 units/day Efficiency of ‘C’ = 3.5 – (2 + 1) = 0.5 units/day Required time taken = (14/0.5) = 28 days
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