Question
A work can be completed by ‘A’ and ‘B’, alone in
7 days and 14 days, respectively. Find the number of days taken by ‘C’ to complete the same work alone if ‘A’, ‘B’ and ‘C’ together can complete the whole work in 4 days.Solution
Let total work = 14 units (LCM of 7 and 14) Efficiency of ‘A’ = (14/7) = 2 units/day Efficiency of ‘B’ = (14/14) = 1 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (14/4) = 3.5 units/day Efficiency of ‘C’ = 3.5 – (2 + 1) = 0.5 units/day Required time taken = (14/0.5) = 28 days
More Time and work Questions
Evaluate:
(24/6) + 3 × (5 - 2)2
- What will come in place of the question mark (?) in the following questions?
120÷(5×2)+8=? 15 * 12 + 35% of 80 + 70% of 130 = ?
672 ÷ 28 × 24 + 363 – 309 =?
14% of 700 + 15% of 900 + 10% of 160 = ?
((1024)n/5 × (42n+1 ))/(16n × 4n-1 ) = ?
What will come in the place of question mark (?) in the given expression?
3.6 X 15 + 4.5 X 12 = 40% of (? - 50)35% of 240 – 6 2 = ? 2 – √256
- What will come in the place of question mark (?) in the given expression?
(40 ÷ 5 + 56 ÷ 8) X (? - 42) = 120
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