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Let total work = 36 units (LCM of 12 and 18) Efficiency of ‘A’ = (36/12) = 3 units/day Efficiency of ‘B’ = (36/18) = 2 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (36/4) = 9 units/day Efficiency of ‘C’ = 9 – (3 + 2) = 4 units/day Required time taken = (36/4) = 9 days
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Binary equivalent of decimal number 35 is
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‘www’ stands for
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