Question
‘A’ alone can do some work in 12 days. ‘B’ and
‘C’ together can do the same work in 6 days. If ‘B’ is half as efficient as ‘A’, then find the time taken by ‘C’ to complete the work alone.Solution
Let the total work be 12 units. {LCM (12 and 6)} So, efficiency of ‘A’ = (12/12) = 1 units/day So, efficiency of ‘B’ = (1/2) = 0.5 unit/day Efficiency of ‘B’ and ‘C’ together = (12/6) = 2 units/day So, efficiency of ‘C’ = 2 – 0.5 = 1.5 units/day So, time taken by ‘C’ to finish the work alone = (12/1.5) = 8 days
More Time and work Questions
(√1296 – 12) × 5 = ? + 40
Simplify: 0.004 × 0.5
(21 X 5) + ? = (480 - 120) ÷ 3
8 × (25 % of 720) – 50 % of 135 % of 840 = ?
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
5/13 × 104 + 1(2/9) × 198 = 133 + ?
What will come in the place of question mark (?) in the given expression?
√(? - 212) - 84 = 81 - 13 X 9
(64/25)? × (125/512)?-1 = 5/8
540 ÷ 6 + 25 % of 120 + ? * 8 = 72 * √9
- What will come in place of the question mark (?) in the following questions?
75% of 240 + 30 = ?
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