Question
βAβ alone can do some work in 12 days. βBβ and
βCβ together can do the same work in 6 days. If βBβ is half as efficient as βAβ, then find the time taken by βCβ to complete the work alone.Solution
Let the total work be 12 units. {LCM (12 and 6)} So, efficiency of βAβ = (12/12) = 1 units/day So, efficiency of βBβ = (1/2) = 0.5 unit/day Efficiency of βBβ and βCβ together = (12/6) = 2 units/day So, efficiency of βCβ = 2 β 0.5 = 1.5 units/day So, time taken by βCβ to finish the work alone = (12/1.5) = 8 days
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