Question
βAβ alone can do some work in 12 days. βBβ and
βCβ together can do the same work in 6 days. If βBβ is half as efficient as βAβ, then find the time taken by βCβ to complete the work alone.Solution
Let the total work be 12 units. {LCM (12 and 6)} So, efficiency of βAβ = (12/12) = 1 units/day So, efficiency of βBβ = (1/2) = 0.5 unit/day Efficiency of βBβ and βCβ together = (12/6) = 2 units/day So, efficiency of βCβ = 2 β 0.5 = 1.5 units/day So, time taken by βCβ to finish the work alone = (12/1.5) = 8 days
(β1296 β 12) Γ 5 = ? + 40
Simplify: 0.004 Γ 0.5
(21 X 5) + ? = (480 - 120) Γ· 3
8 Γ (25 % of 720) β 50 % of 135 % of 840 = ?
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
5/13 Γ 104 + 1(2/9) Γ 198 = 133 + ?
What will come in the place of question mark (?) in the given expression?
β(? - 212) - 84 = 81 - 13 X 9
(64/25)?Β Γ (125/512)?-1Β =Β 5/8
540 Γ· 6 + 25 % of 120 + ? * 8 = 72 * β9
- What will come in place of the question mark (?) in the following questions?
75%Β ofΒ 240 + 30 = ?