Question
‘A’ alone can do some work in 10 days. ‘B’ and
‘C’ together can do the same work in 12 days. If ‘B’ is half as efficient as ‘A’, then find the time taken by ‘C’ to complete the work alone.Solution
Let the total work be 60 units. {LCM (10 and 12)} So, efficiency of ‘A’ = (60/10) = 6 units/day So, efficiency of ‘B’ = (6 x 0.5) = 3 unit/day Efficiency of ‘B’ and ‘C’ together = (60/12) = 5 units/day So, efficiency of ‘C’ = 5 – 3 = 2 units/day So, time taken by ‘C’ to finish the work alone = (60/2) = 30 days
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