Let the total work be 60 units. {LCM (10 and 12)} So, efficiency of ‘A’ = (60/10) = 6 units/day So, efficiency of ‘B’ = (6 x 0.5) = 3 unit/day Efficiency of ‘B’ and ‘C’ together = (60/12) = 5 units/day So, efficiency of ‘C’ = 5 – 3 = 2 units/day So, time taken by ‘C’ to finish the work alone = (60/2) = 30 days
I: x2 - 33x + 242 = 0
II: y2 - 4y - 77 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
I. p²= ∛1331
II. 2q² - 21q + 55 = 0
I. x ² + 5 x + 6 = 0
II. y²+ 7 y + 12= 0
...Let 's' represent the sum of the highest root of equations I and III, and 'r' denote the product of the lowest root of equation I and the highest root o...
I. x2– 9x + 18 = 0
II. y2– 5y + 6 = 0
I. p2 +7p + 10 = 0 II. q2- q – 6 = 0
I. 6p² + 17p + 12 = 0
II. 12q² - 25q + 7 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
Equation 1: x² - 90x + 2025 = 0
Equation 2: y² - 88y + 1936 = 0
