Question
‘A’ alone can do some work in 13 days. ‘B’ and
‘C’ together can do the same work in 18 days. If ‘B’ is half as efficient as ‘A’, then find the time taken by ‘C’ to complete the work alone.Solution
Let the total work be 234 units. {LCM (13 and 18)} So, efficiency of ‘A’ = (234/13) = 18 units/day So, efficiency of ‘B’ = (18 x 0.5) = 9 unit/day Efficiency of ‘B’ and ‘C’ together = (234/18) = 13 units/day So, efficiency of ‘C’ = 13 – 9 = 4 units/day So, time taken by ‘C’ to finish the work alone = (234/4) = 58.5 days
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