Question
A can complete a job in 12 days, B in 18 days. They work together for 6 days, then A leaves. How many more days will B take to finish the remaining work?
Solution
ATQ, A’s 1 day work = 1/12, B’s = 1/18 Together for 6 days: Work done = 6 × (1/12 + 1/18) = 6 × (5/36) = 5/6 Remaining = 1 - 5/6 = 1/6 B alone: Time = (1/6) ÷ (1/18) = 3 days
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