Question
'A' alone can do some work in 15 days. 'B' is 40% more
efficient than 'A'. 'A' worked alone for 8 days and left. How much time (in days) does 'B' need to finish the remaining work?Solution
Let the efficiency of 'A' be x units/day.
So, efficiency of 'B' = 1.4x units/day.
Total work = 15 × x = 15x units.
Work done by 'A' in eight days = 8 × x = 8x units.
Remaining work = 15x − 8x = 7x units.
Time taken by 'B' to finish the remaining work = ({7x/1.4x} = 5) days.
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