Question
'A' alone can do some work in 12 days. 'B' is 50% more
efficient than 'A'. 'A' worked alone for 3 days and left. How much time (in days) does 'B' need to finish the remaining work?Solution
Let the efficiency of 'A' be x units/day.
So, efficiency of 'B' = 1.5x units/day.
Total work = 12 × x = 12x units.
Work done by 'A' in three days = 3 × x = 3x units.
Remaining work = 12x − 3x = 9x units.
Time taken by 'B' to finish the remaining work = ({9x/1.5x} = 6) days.
I. p2Â - 53p + 672 = 0
II. q2Â - 27q + 126Â = 0
I. x2 – 3(x + 5) = -11
II. y2 – 4(y + 2) = -2y
I. 27x6 - 152x3 + 125 = 0
II. 216y6 - 91y3 + 8 = 0
I. x2 - 4x – 21 = 0
II. y2 + 12y + 20 = 0
I. 84x² - 167x - 55 = 0
II. 247y² + 210y + 27 = 0
I. 27x² + 120x + 77 = 0
II. 56y² + 117y + 36 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 56x² - 99x + 40 = 0
II. 8y² - 30y + 25 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 88x + 100 = 0
Equation 2: 17y² - 79y + 90...
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