Question
'A' alone can do some work in 10 days. 'B' is 25% more
efficient than 'A'. 'A' worked alone for 5 days and left. How much time (in days) does 'B' need to finish the remaining work?Solution
Let the efficiency of 'A' be x units/day.
So, efficiency of 'B' = 1.25x units/day.
Total work = 10 × x = 10x units.
Work done by 'A' in five days = 5 × x = 5x units.
Remaining work = 10x − 5x = 5x units.
Time taken by 'B' to finish the remaining work = ({5x/1.25x} = 4) days.
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