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    Question

    'A' alone can do some work in 10 days. 'B' is 25% more

    efficient than 'A'. 'A' worked alone for 5 days and left. How much time (in days) does 'B' need to finish the remaining work?
    A 5 days Correct Answer Incorrect Answer
    B 6 days Correct Answer Incorrect Answer
    C 4 days Correct Answer Incorrect Answer
    D 9 days Correct Answer Incorrect Answer
    E 8 days Correct Answer Incorrect Answer

    Solution

    Let the efficiency of 'A' be x units/day.
    So, efficiency of 'B' = 1.25x units/day.
    Total work = 10 × x = 10x units.
    Work done by 'A' in five days = 5 × x = 5x units.
    Remaining work = 10x − 5x = 5x units.
    Time taken by 'B' to finish the remaining work = ({5x/1.25x} = 4) days.

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