Question
In an examination, the passing percentage is 35%. 'P'
scores 8% less than the passing marks, and 'Q' scores 25% less than 'P'. What percentage less (up to two decimal places) than the combined total of 'P' and 'Q's marks should 'R' score in order to pass the exam with the minimum required marks?Solution
Let the maximum marks = 100x Passing marks = 35x P’s score = (35x)(1 – 0.08) = 32.2x Q’s score = (32.2)(1 – 0.25) = 24.15x Sum of the scores of ‘P’ and ‘Q’ = 24.15x + 32.2x = 56.35x Required percentage = {(56.35x – 35x)/56.35x} × 100 = 37.88%
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