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    Question

    ‘M’ has 15% less balls than ‘N’. ‘N’ has 10%

    more balls than ‘O’. By how much percent the number of balls with ‘M’ are less than those with ‘O’?
    A 8.5% Correct Answer Incorrect Answer
    B 6.5% Correct Answer Incorrect Answer
    C 12.5% Correct Answer Incorrect Answer
    D 18.5% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let, number of balls with ‘N’ = 11z

    Number of balls with ‘M’ = 0.85 × 11z = 9.35z

    Number of balls with ‘O’ = (11z/1.1) = 10z

    So, required percentage = {(10z – 9.35z)/10z} × 100 = 6.5%

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