New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    There is a rectangular paper, whose length and breadth

    are in the ratio 6:5, respectively and it has a perimeter of 44 metres. If a triangular piece with height of 9 metres and base of 16 metres is cut out from the given paper then find the area (in m2) of the remaining paper.
    A 47 Correct Answer Incorrect Answer
    B 45 Correct Answer Incorrect Answer
    C 42 Correct Answer Incorrect Answer
    D 48 Correct Answer Incorrect Answer

    Solution

    Let the length and breadth of the rectangular be ‘6x’ metres and ‘5x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (6x + 5x) = 22 x metres So, 22x = 44 So, x = (44/22) = 2 So, area of the entire paper = length × breadth = (6 × 2) × (5 × 2) = 12 × 10 = 120 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 9 × 16 = 72 m2 So, area of the remaining paper = 120 – 72 = 48 m2

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