There is a rectangular paper, whose length and breadth are in the ratio 6:5, respectively and it has a perimeter of 44 metres. If a triangular piece with height of 9 metres and base of 16 metres is cut out from the given paper then find the area (in m2) of the remaining paper.
Let the length and breadth of the rectangular be ‘6x’ metres and ‘5x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (6x + 5x) = 22 x metres So, 22x = 44 So, x = (44/22) = 2 So, area of the entire paper = length × breadth = (6 × 2) × (5 × 2) = 12 × 10 = 120 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 9 × 16 = 72 m2 So, area of the remaining paper = 120 – 72 = 48 m2
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