New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    There is a rectangular paper, whose length and breadth

    are in the ratio 5:4, respectively and it has a perimeter of 90 metres. If a triangular piece with height of 11 metres and base of 12 metres is cut out from the given paper then find the area (in m2) of the remaining paper.
    A 424 Correct Answer Incorrect Answer
    B 414 Correct Answer Incorrect Answer
    C 404 Correct Answer Incorrect Answer
    D 434 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the length and breadth of the rectangular be ‘5x’ metres and ‘6x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (5x + 4x) = 18 x metres So, 18x = 90 So, x = (90/18) = 5 So, area of the entire paper = length × breadth = (5 × 5) × (4 × 5) = 25 × 20 = 500 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 11 × 12 = 66 m2 So, area of the remaining paper = 500 – 66 = 434 m2

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