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Let the length and breadth of the rectangular be ‘5x’ metres and ‘6x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (5x + 4x) = 18 x metres So, 18x = 90 So, x = (90/18) = 5 So, area of the entire paper = length × breadth = (5 × 5) × (4 × 5) = 25 × 20 = 500 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 11 × 12 = 66 m2 So, area of the remaining paper = 500 – 66 = 434 m2
13³ + 1.3² + 1.03¹ + 1.003 = ?
?% of (742÷ 7.911) = (11.01)2
(363.89% of 224.98 – 319.86% of 134.94) ÷ ? = √(134.88 ÷ 15.25)
6.992 + (2.01 × 2.98) + ? = 175.03
√323.89 × (3.20) ÷ 9.02 =?
? = 22.08 + 13.99 × 22.07
22.22 × 8.99 + 142.15 = ?
(17.98% of 249.99) - 4.998 = √?