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Start learning 50% faster. Sign in nowLet the length and breadth of the rectangular be ‘6x’ metres and ‘7x’ metres, respectively Then, perimeter of the paper = 2 × (length + breadth) = 2 × (6x + 7x) = 26 x metres So, 26x = 78 So, x = (78/26) = 3 So, area of the entire paper = length × breadth = (6 × 3) × (7 × 3) = 18 × 21 = 378 m2 Area of the triangular piece = (1/2) × base × height = (1/2) × 14 × 10 = 70 m2 So, area of the remaining paper = 378 – 70 = 308 m2
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Statement I: Height of B is more than A...
Who is brother in law of Y?
I. Y is mother of Z and is married to the brother of A, who is female.
II. V and X are brothers of A. U is wife of X.
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Five persons L, N, O, P and Q, who all are of different weights. Who among the following is the lightest?
Statement I: N is lighter than only one...
How is B related to C?
I. C and D are the sons of E. B is son of E’s father.
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II. &l...
If it is given that 1PS, 3TS and TQ2, is P greater than Q?
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II. 2X...