Question
The area of a square is 576 cm2 which is 172
cm2 less than that of a rectangle. Find the perimeter of the rectangle if the length of the rectangle is 10 cm more than the length of each side of the square.Solution
Area of the square = 576 cm2 Length of each side of the square = √576 = 24 cm Area of the rectangle = 576 + 172 = 748 cm2 Length of the rectangle = 10 + 24 = 34 cm So, area of rectangle = length × breadth = 34 × breadth = 748 cm2 So, breadth of the rectangle = 748/34 = 22 cm Therefore, perimeter of the rectangle = 2 × (length +breadth) = 2 × (22 + 34) = 112 cm
Data warehouse has historical data
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list1 = ['physics', 'chemistry', 1997, 2000]
list2 = [1, 2, 3, 4, 5, 6, 7 ]
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