Question
The area of a square is 576 cm2 which is 172
cm2 less than that of a rectangle. Find the perimeter of the rectangle if the length of the rectangle is 10 cm more than the length of each side of the square.Solution
Area of the square = 576 cm2 Length of each side of the square = √576 = 24 cm Area of the rectangle = 576 + 172 = 748 cm2 Length of the rectangle = 10 + 24 = 34 cm So, area of rectangle = length × breadth = 34 × breadth = 748 cm2 So, breadth of the rectangle = 748/34 = 22 cm Therefore, perimeter of the rectangle = 2 × (length +breadth) = 2 × (22 + 34) = 112 cm
The H.C.F. of two numbers is 16 and the other two factors of their L.C.M. are 4 and 13. The larger of the two numbers is:
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The product of two numbers is 5760 and their GCD is 48. What is the LCM?
Find the HCF of two numbers if LCM and product of those two numbers are 45 and 630 respectively.
- Find the HCF of 84 and 630.
- The product of two numbers is 4620 and their L.C.M is 210. What is the H.C.F of the two numbers?
Determine the LCM of (8/35) and (24/5).
Sum of the two numbers is 40 and their HCF and LCM are 8 and 48, respectively. Find the sum of reciprocal of the given two numbers.
Determine the difference between the LCM and HCF of 18, 24, and 36.
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