Question
The area of a square is 729 cm2 which is 48
cm2 less than that of a rectangle. Find the perimeter of the rectangle if the length of the rectangle is 10 cm more than the length of each side of the square.Solution
Area of the square = 729 cm2 Length of each side of the square = √729 = 27 cm Area of the rectangle = 729 + 48 = 777 cm2 Length of the rectangle = 10 + 27 = 37 cm So, area of rectangle = length × breadth = 37 × breadth = 777 cm2 So, breadth of the rectangle = 777/37 = 21 cm Therefore, perimeter of the rectangle = 2 × (length +breadth) = 2 × (21 + 37) = 116 cm
According to National Forest Policy, 1988; the minimum forest cover should be maintained
It is advised to add gypsum to manure in the cattle shed. Reason behind it is?
Bromelin alkaloid is found in
Angoumois belongs to which orderÂ
Which bacterial phylum is one of the most predominant in the phyllosphere?
Which one of the following is a competitive market?
Kufri badshah variety of potato is resistant toÂ
Which recommendation proposed effective administrative decentralization through elected local self-government bodies?
International Food Safety standards are developed by
Water movement in a saturated soil is governed by which law?
Relevant for Exams:
