Question
The area of a square is 729 cm2 which is 48
cm2 less than that of a rectangle. Find the perimeter of the rectangle if the length of the rectangle is 10 cm more than the length of each side of the square.Solution
Area of the square = 729 cm2 Length of each side of the square = √729 = 27 cm Area of the rectangle = 729 + 48 = 777 cm2 Length of the rectangle = 10 + 27 = 37 cm So, area of rectangle = length × breadth = 37 × breadth = 777 cm2 So, breadth of the rectangle = 777/37 = 21 cm Therefore, perimeter of the rectangle = 2 × (length +breadth) = 2 × (21 + 37) = 116 cm
(7.992/√?) + √16/? = 14.032/?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
15.22 × 9.99 + 150.15 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will replace the question mark (?) in the following?
29.99...
(√780 + 111.98) ÷ 6.95 + 39.95% of 179.98 = ?
25, 28, 26, 29, 27, ?
30.11% of 149.99 + √195.97 ÷ 7.02 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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