Question
Aβ and βBβ alone can do a certain work in 20 days
and 30 days, respectively. Both started the work together but after βxβ days βAβ left the work and the rest work was completed by B alone in β2xβ days. Find the total time taken to complete the whole work in this way.Solution
Total work = 60 units (LCM of 20 and 30) Efficiency of βAβ = 60/20 = 3 units/day Efficiency of βBβ = 60/30 = 2 units/day According to the question, βAβ worked for βxβ days and βBβ worked for β2x days. Therefore, 3x + 2 Γ 2x = 120 Or 3x + 4x = 60 Or x = 60/7days total time taken to complete the whole work = 2Γ60/7=120/7days
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