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    Question

    P is 60% more efficient than Q. P takes 30 more days to

    finish a work as compared to the number of days taken by P and Q together to finish the same work. Find the time taken by Q to finish the same work alone.
    A 125days Correct Answer Incorrect Answer
    B 120days Correct Answer Incorrect Answer
    C 124.8days Correct Answer Incorrect Answer
    D 136.2days Correct Answer Incorrect Answer

    Solution

    Let efficiency of P = p and efficiency of Q = q p = 160% of q => p: q = 8: 5 Let time required by P and Q together to finish this job be тАЬtтАЭ. (p + q) ├Чt = W => 13x ├Ч t = W┬а┬а┬а тАж. (1) ATQ- p ├Ч (t + 30) = W ┬а => 8x ├Ч (t + 30) = W┬а┬а┬а┬а┬а┬а┬а┬а тАж (2) By solving above two equations we get t = 48 13x ├Ч 48 = 5x ├Ч T ┬а => T = 124.8 days

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