Question
Two workers, βXβ and βYβ, can finish a job in 25
days together. If βXβ is 25% more efficient than βYβ, find the number of days βYβ alone would take to complete the job.Solution
Let the efficiency of βYβ be 8x units. Efficiency of βXβ = 8x Γ 1.25 = 10x units Total work = 25 Γ (8x + 10x) = 450x units Time taken by βYβ alone = 450x Γ· 8x = 56.25 days
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