Question
βAβ alone can complete a work in 50 hours. βAβ
started the work alone and left after working on it for 10 hours. If βBβ completed the rest of the work in 10 hours then find the time taken by βAβ and βBβ together to complete the whole work.Solution
Let the total work = 250 units Then, efficiency of βAβ = (250/50) = 5 units/hour Work completed by βAβ alone in 10 hours = 5 Γ 10 = 50 units Remaining work = 250 β 50 = 200 units So, efficiency of βBβ = 200/10 = 20 units/hour Therefore, combined efficiency of βAβ and βBβ = 20 + 5 = 25 units/hour So, time taken by βAβ and βBβ together to complete the work = (250/25) = 10 hours
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