Question
‘A’ alone can complete a work in 50 hours. ‘A’
started the work alone and left after working on it for 10 hours. If ‘B’ completed the rest of the work in 10 hours then find the time taken by ‘A’ and ‘B’ together to complete the whole work.Solution
Let the total work = 250 units Then, efficiency of ‘A’ = (250/50) = 5 units/hour Work completed by ‘A’ alone in 10 hours = 5 × 10 = 50 units Remaining work = 250 – 50 = 200 units So, efficiency of ‘B’ = 200/10 = 20 units/hour Therefore, combined efficiency of ‘A’ and ‘B’ = 20 + 5 = 25 units/hour So, time taken by ‘A’ and ‘B’ together to complete the work = (250/25) = 10 hours
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