Question
A buffalo alone can plough field βAβ in 20 days. A
Bull alone can plough the field βAβ in 32 days. Find the number of days taken by 2 bulls and 2 buffalo to together plough field βBβ that is 30% larger than field βAβ?Solution
Let the total work done to plough field βAβ = 160 units (LCM of 20 and 32) Then, efficiency of a buffalo = (160/20) = 8 units/day Efficiency of a bull = (160/32) = 5 units/day Total work required to plough field βBβ = 160 Γ 1.30 = 208 units Combined efficiency of 2 bulls and 2 buffalo = 2 Γ 5 + 2 Γ 8 = 26 units So, number of days required to plough field βBβ = 208/26 = 8 days
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