Question
A buffalo alone can plough field βAβ in 20 days. A
Bull alone can plough the field βAβ in 10 days. Find the number of days taken by 1 bulls and 4 buffalo to together plough field βBβ that is 35% larger than field βAβ?Solution
Let the total work done to plough field βAβ = 20 units (LCM of 20 and 10) Then, efficiency of a buffalo = (20/20) = 1 units/day Efficiency of a bull = (20/10) = 2 units/day Total work required to plough field βBβ = 20 Γ 1.35 = 27 units Combined efficiency of 1 bulls and 4 buffalo = 2 Γ 1 + 4 Γ 1 = 6 units So, number of days required to plough field βBβ = 27/6 = 4.5 days
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