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    Question

    A buffalo alone can plough field β€˜A’ in 20 days. A

    Bull alone can plough the field β€˜A’ in 10 days. Find the number of days taken by 1 bulls and 4 buffalo to together plough field β€˜B’ that is 35% larger than field β€˜A’?
    A 2.5 days Correct Answer Incorrect Answer
    B 3.5 days Correct Answer Incorrect Answer
    C 4.5 days Correct Answer Incorrect Answer
    D 1.5 days Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the total work done to plough field β€˜A’ = 20 units (LCM of 20 and 10) Then, efficiency of a buffalo = (20/20) = 1 units/day Efficiency of a bull = (20/10) = 2 units/day Total work required to plough field β€˜B’ = 20 Γ— 1.35 = 27 units Combined efficiency of 1 bulls and 4 buffalo = 2 Γ— 1 + 4 Γ— 1 = 6 units So, number of days required to plough field β€˜B’ = 27/6 = 4.5 days

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