Question
A buffalo alone can plough field βAβ in 20 days. A
Bull alone can plough the field βAβ in 10 days. Find the number of days taken by 1 bulls and 4 buffalo to together plough field βBβ that is 35% larger than field βAβ?Solution
Let the total work done to plough field βAβ = 20 units (LCM of 20 and 10) Then, efficiency of a buffalo = (20/20) = 1 units/day Efficiency of a bull = (20/10) = 2 units/day Total work required to plough field βBβ = 20 Γ 1.35 = 27 units Combined efficiency of 1 bulls and 4 buffalo = 2 Γ 1 + 4 Γ 1 = 6 units So, number of days required to plough field βBβ = 27/6 = 4.5 days
Let (Xi, I β₯ 1} be independent and identically distributed random variables with P(Xi =1) = p = 1-P(Xi = 0), Sn = βni = 1 X i . The dist...
The problem of statistics is given in two sections of same standard. The odds against for section X to solve the problem are 4:3 and odds in favor to s...
Two random variables X and Y are said to be independent if:
The sample sizes for two cases were 15 each with means as 104 and 114 respectively and variances as 200 and 510 respectively.
Let the null hyp...
If Z1, Z2,β¦Zn are n independent standard normal variates, then Ξ£ni=1 Z2i will follow:
For the study purpose, the mean of the observations is 148 gm and standard deviation is 17.4 gm. Approximately, the coefficient of variation equals to:
The interquartile range excludes ___ of the values.
Which of the following is the most relevant for deriving a point estimate?
The probability of getting 9 cards of the same suit in one hand at a game of bridge is
If the occurrence of events follows Poisson Process with mean rate Ξ», then inter-occurrence time of events will follow:
