Question
A, B and C can complete a work in 2 days. If A alone can
complete the same work in 6 days and B in 4 days, how long will it take for C to finish the work alone?Solution
ATQ: A + B + C = 2 A = 6 B = 4 Total work = 12 (LCM of 2, 6 and 4) A + B + C = 12/2 = 6 A = 12/6 = 2 B = 12/4 = 3 efficiency of C = (6 - (2 + 3)) = 1 Therefore, c will take 12/1 = 12 days
Statements:
V ≤ P < S = B; T < U ≤ I = B; N < J < T
Conclusions:
I. J > P
II. N < S
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