Question
A can complete a work in 10 days and B can complete it
in 15 days. They work together for 4 days, then A leaves. In how many days will B finish the remaining work alone?Solution
ATQ, Work/day together = 1/10 + 1/15 = (3+2)/30 = 1/6 Work done in 4 days = 4×(1/6) = 2/3 Remaining work = 1 − 2/3 = 1/3 B’s work/day = 1/15 Time = (1/3) ÷ (1/15) = (1/3)×15 = 5 days
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