Question
Anjali,' 'Bheem,' and 'Chetna' started a business
together with initial investments of Rs. 3,875, Rs. (B + 2700), and Rs. 'B,' respectively. After 16 months, 'Bheem' reduced his investment by half, and 'Chetna' increased his investment by Rs. 900. If the ratio of the profit received by 'Bheem' and 'Chetna' after 3 years is 26:25, respectively, then find the difference between the initial investments made by 'Anjali' and 'Chetna.'Solution
ATQ, Let the initial investment of ‘Chetna’ = Rs.‘2a’ Then, initial investment of ‘Bheem’ = Rs.(2a + 2700) Investment of ‘Bheem’ after 16 months = (2a+ 2700)/2 = Rs. (a + 1350) Investment of ‘Chetna’ after 16 months = Rs.(2a + 900) Ratio of profit shares of ‘Bheem’ to that of ‘Chetna’ = [(2a + 2700) × 16 + (a + 1350) × 20]:[(2a × 16) + (2a + 900) × 20] = 26:25 Or, (8a + 10800 + 5a + 6750):(8a + 10a + 4500) = 26:25 Or, (13a + 17550) × 25 = (18a + 4500) × 26 Or, 325a + 438750 = 468a + 117000 Or, 321750 = 143a Or, a = 2250 So, initial investment of ‘Chetna’ = 2a = Rs. 4500 Difference between initial investments of ‘Anjali’ and ‘Chetna’ = 4500 – 3875 = Rs.625
(408 × 680)÷(20% of 680) = (250 × 260)÷ 10 + ? – 4500
If (a + b) = 9 and ab = 14, find the value of (a² + b²).
If x2 – 5x + 1 = 0, then find the value of {x2 + (1/x2)}.
If x = 15, find x5 - 16x4 + 16x3 - 16x2 + 16x - 16 = ?
Find ‘x’ if (x³+3x)/(3x²+1) = 189/61
if √1+x/121 = 13/11 then find the value of x.
- If x² - 2x + 1 = 0, then find the value of (x³ + x⁻³)(x + x⁻¹).
If x = (2+√3)/(2-√3), y = (2-√3)/(2+√3). Then find out the value of (x²+y²-xy)/(x²+y²+xy)?
- If 4x + y = 18 and xy = - 10, what is the value of 4x - y?
If the sum of three numbers is zero, then which of the options below will always be equal to the value of the sum of the cubes of those numbers?
Relevant for Exams:
