Question
Working alone, 'C' can complete a job in 30 days. 'D'
takes 20% less time than 'C' to finish the same job. Calculate the percentage of work done by 'C' and 'D' together in 4 days.Solution
ATQ, Time taken by 'D' alone: 0.8×30=24 days Total work: LCM of 24 and 30 = 120 units Efficiency of 'C': 120/30=4 units/day Efficiency of 'D': 120/24=5 units/day Combined efficiency of 'C' and 'D': 4+5=9 units/day Work done in 4 days: 9×4=36 units Percentage of total work done: (36/120)×100=30 Therefore, 'C' and 'D' together complete 30% of the work in 4 days.
?% of (112.31 ÷ 13.97 × 90.011) = 359.98
40.22 of 249.98% + 459.99 ÷ 23.18 = ?
456.9 + 328.10 - 122.98 = ? + 232.11
108.31% of (4.9/9.012) of ? = 23.9% of 2499.9
A man lost one-fourth of his initial amount in the gambling after playing three rounds. The rule of Gambling is that if he wins he will receive Rs. 1000...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
256.12 ÷ 7.92 + 26.11 × 7.82 – 44.09 = ?2