Question
There is enough food in a camp to last for 50 days if
each of the 80 soldiers present at the camp eat 2 times a day. After 20 days, 30 soldiers left the camp and remaining ate only once a day. For how many days (from start) will the food last?Solution
Let the eating capacity of each soldier be 'x' units So, total food at the camp = (50 X 80 X 2 X x) = '8000x' units And food remaining after 20 days = 8000x - (20 X 80 X 2 X x) = '4800x' units So, required time = 4800x ÷ (x X 1 X 50) = 96 days So, the food will last for a total of 96 + 20 = 116 days
If 152,   242,    x ,  332,   404,    314,
then find the value of (2x – 1)?
...3 5 7 25 85 481
...60  61  126  387  ?   7845
2556   636    156    ?    6
9Â Â Â 4.5Â Â Â 4.5Â Â Â 9Â Â Â 36Â Â Â ?
14 20 35 ? 433 2167
...63 189 315 378 567 693
...11Â Â Â 46Â Â Â 109Â Â Â 208Â Â Â Â 351Â Â Â Â ?
12 11 18 34 89.5 259.5
...Choose the correct alternative
21: 3 ∷ 574: ?
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