Question
Aβ and βBβ together can complete a work in 10 days
while βAβ takes 30 days to complete the same work alone. If βCβ is 50% more efficient than βBβ, then find the time taken by βCβ alone to complete the whole work.Solution
Let the total work = 30 units Efficiency of (A + B) = 30/10 = 3 units/day Efficiency of βAβ = 30/30 = 1 unit/day Therefore, efficiency of βBβ = 3 β 1 = 2 units/day Efficiency of βCβ = 1.5 Γ 2 = 3 units/day Required time taken = 30/3 = 10 days
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