Question

    ‘M’ and ‘N’ can do a piece of work in 9 days and

    18 days, respectively. ‘M’ started working alone and was replaced by ‘N’ after 3 days. In how many days can ‘N’ complete the remaining amount of work alone?
    A 6 days Correct Answer Incorrect Answer
    B 9 days Correct Answer Incorrect Answer
    C 15 days Correct Answer Incorrect Answer
    D 12 days Correct Answer Incorrect Answer

    Solution

    Let the total work be 18 units (LCM of 9 and 18) Efficiency of ‘M’ = 18/9 = 2 units/day Efficiency of ‘N’ = 18/18 = 1 unit/day Let the number of days taken by ‘N’ to finish the remaining amount of work be ‘x’ ATQ, (2 × 3) + x = 18 Or, x = 18 – 6 Or, x = 12 Therefore, time taken by ‘N’ to complete the remaining work alone = 12 days

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