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12 men = 6 days Work done by 12 men in one day = 1/6 Work done by 12 men in 2 days = 1/6 × 2 = 1/3 Remaining work = 1 - 1/3 = 2/3 Now, 4 men joined them Therefore, 2/3 rd of work is done by 16 men in x days We have the formula, M1 × D1 / W1 = M2 × D2 / W2 Here, M1 = 12, D1 = 2 and W1 = 1/3 M2 = 16, D2 = x and W2 = 2/3 (12 × 2)/(1/3) = (16 × x)/(2/3) x = 3 days ALTERNATE SHORTCUT METHOD M1 × D1 = M2 × D2 12 × 6 = 12 × 2 + (12 + 4) × x 72 = 24 + 16 x 48 = 16 x So x = 3days
I: x2 + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. x2 - 11x + 24 = 0
II. y² - 5y + 6 = 0
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
I. p2+ 2p – 8 = 0 II. q2 – 5q + 6 = 0
'r' is one of the roots of equation (r - 1)p2 - (5r + 2)p + 12 = 0 and sum of roots is (32/5), Determine the two roots of the equation.
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the...
I. 64x2 - 64x + 15 = 0
II. 21y2 - 13y + 2 =0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 92x + 73 = 0
Equation 2: 17y² - 76y + 59 = 0
I. 144x² - 163x - 65 = 0
II. 91y² - 128y -48 = 0
I. 10p² + 21p + 8 = 0
II. 5q² + 19q + 18 = 0