Question
Riya can do a piece of work in 30 days, and Mehul can do
it in 45 days. Find the number of days Kabir will take to complete the job if he is 20% more efficient than Riya and Mehul working together.Solution
Let total amount of work = 90 units (LCM of 30 and 45) Work done by Riya in one day = 90 / 30 = 3 units Work done by Mehul in one day = 90 / 45 = 2 units Combined = 3 + 2 = 5 units Kabir’s efficiency = 1.2 × 5 = 6 units/day Time taken by Kabir = 90 / 6 = 15 days
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