Question
'C' can complete a work in 18 days whereas 'D' can do
the same work in 30 days.They started working together but 'C' worked with 60% of his efficiency while 'D' worked with 50% of his efficiency. Find the total time taken by them to complete the work this way.Solution
ATQ, Let the total work be 90 units (LCM of 18 and 30) So, efficiency of 'C' = (90/18) = 5 units/day And efficiency of 'D' = (90/30) = 3 units/day New efficiency of 'C' = 60% of 5 = (0.6) X 5 = 3 units/day New efficiency of 'D' = 50% of 3 = (0.5) X 3 = 1.5 units/day So, required time =(90/(3+1.5) = 90/4.5 = 20 days
Which innovative platform was officially launched by Member of NITI Aayog, Professor Ramesh Chand, to streamline and enhance data management in the agri...
A plant showing yellowing between the veins (interveinal chlorosis) on older leaves is most likely deficient in which essential nutrient?
Land equivalent ration (LER) is used to evaluate which of the following option?
For the analysis of variance of data from plot sampling in a CRD with 't' treatments, ‘r’ replications and 's' sampling units per plot, sampling err...
Carbohydrate is present only around ……………… of total animal body
The facility of national portability of ration card is named as____
FSSAI has constituted scientific bodies, namely the Scientific Committee and ……………. subject specific Scientific Panels (SP).
...Hardy-Weinberg law is applicable for maintainence of genetic purity of
Which one is Amino acid among the following ?
RM (Reichert Meissl) Number test is done to check the purity of?
Relevant for Exams:
