Question
'C' can complete a work in 18 days whereas 'D' can do
the same work in 30 days.They started working together but 'C' worked with 60% of his efficiency while 'D' worked with 50% of his efficiency. Find the total time taken by them to complete the work this way.Solution
ATQ, Let the total work be 90 units (LCM of 18 and 30) So, efficiency of 'C' = (90/18) = 5 units/day And efficiency of 'D' = (90/30) = 3 units/day New efficiency of 'C' = 60% of 5 = (0.6) X 5 = 3 units/day New efficiency of 'D' = 50% of 3 = (0.5) X 3 = 1.5 units/day So, required time =(90/(3+1.5) = 90/4.5 = 20 days
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