Question
A alone can finish a piece of work in 10 days and B
alone can finish it in 15 days. They work together for 3 days and the remaining work is finished by C in 4 days. In how many days can C alone finish the entire work?Solution
ATQ, Let total work = 1 unit Aās 1-day work = 1/10 Bās 1-day work = 1/15 Together (A + B) 1-day work = 1/10 + 1/15 LCM of 10 and 15 = 30 = 3/30 + 2/30 = 5/30 = 1/6 Work done in 3 days = 3 Ć (1/6) = 1/2 So remaining work = 1 ā 1/2 = 1/2 C finishes 1/2 work in 4 days Cās 1-day work = (1/2) / 4 = 1/8 So C alone would finish full work in 8 days.
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