Question
A alone can finish a piece of work in 10 days and B
alone can finish it in 15 days. They work together for 3 days and the remaining work is finished by C in 4 days. In how many days can C alone finish the entire work?Solution
ATQ, Let total work = 1 unit A’s 1-day work = 1/10 B’s 1-day work = 1/15 Together (A + B) 1-day work = 1/10 + 1/15 LCM of 10 and 15 = 30 = 3/30 + 2/30 = 5/30 = 1/6 Work done in 3 days = 3 × (1/6) = 1/2 So remaining work = 1 − 1/2 = 1/2 C finishes 1/2 work in 4 days C’s 1-day work = (1/2) / 4 = 1/8 So C alone would finish full work in 8 days.
Find the ratio of the area of an equilateral triangle of side ‘a’ cm to the area of a square having each side equal to ‘a’ cm.
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(5/9 of 2699.81) + (49.88% of 144.18) - (2/7 of 489.77) = ?
59.978% of 800.315 - 229.95 = ? - 24.95% of 200.15
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will replace the question mark (?) in the following?
? =...
960.02 of 238.89 ÷ 144.01 of 79.97 = ?
 (1782 ÷ 11.98) ÷ 2.92 × 35.89 + 25% of 541 – 67% of 1299 = ?
99.99% of 9.99 + 299.98% of 129.98 = ?2Â
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