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    Question

    Individual ‘M’ can do a piece of work in 40 days,

    while ‘M’ and ‘N’ together can do it in 16 days. If ‘N’ worked alone for 10 days and left, how many days will ‘M’ take to complete the remaining work?
    A 25 days Correct Answer Incorrect Answer
    B 40 days Correct Answer Incorrect Answer
    C 75 days Correct Answer Incorrect Answer
    D 16 days Correct Answer Incorrect Answer

    Solution

    Let the total work = 80 units {L.C.M of 40 and 16}
    Then, efficiency of ‘M’ = 80 ÷ 40 = 2 units/day
    Combined efficiency of ‘M’ and ‘N’ = 80 ÷ 16 = 5 units/day
    So, efficiency of ‘N’ = 5 – 2 = 3 units/day
    So, work done by ‘N’ alone in 10 days = 3 × 10 = 30 units
    Remaining work = 80 – 30 = 50 units
    Time taken by 'M' alone to complete the remaining work = 50 ÷ 2 = 25 days

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