Question
Individual ‘M’ can do a piece of work in 40 days,
while ‘M’ and ‘N’ together can do it in 16 days. If ‘N’ worked alone for 10 days and left, how many days will ‘M’ take to complete the remaining work?Solution
Let the total work = 80 units {L.C.M of 40 and 16}
Then, efficiency of ‘M’ = 80 ÷ 40 = 2 units/day
Combined efficiency of ‘M’ and ‘N’ = 80 ÷ 16 = 5 units/day
So, efficiency of ‘N’ = 5 – 2 = 3 units/day
So, work done by ‘N’ alone in 10 days = 3 × 10 = 30 units
Remaining work = 80 – 30 = 50 units
Time taken by 'M' alone to complete the remaining work = 50 ÷ 2 = 25 days
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