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      Question

      Individual ‘M’ can do a piece of work in 40 days,

      while ‘M’ and ‘N’ together can do it in 16 days. If ‘N’ worked alone for 10 days and left, how many days will ‘M’ take to complete the remaining work?
      A 25 days Correct Answer Incorrect Answer
      B 40 days Correct Answer Incorrect Answer
      C 75 days Correct Answer Incorrect Answer
      D 16 days Correct Answer Incorrect Answer

      Solution

      Let the total work = 80 units {L.C.M of 40 and 16}
      Then, efficiency of ‘M’ = 80 ÷ 40 = 2 units/day
      Combined efficiency of ‘M’ and ‘N’ = 80 ÷ 16 = 5 units/day
      So, efficiency of ‘N’ = 5 – 2 = 3 units/day
      So, work done by ‘N’ alone in 10 days = 3 × 10 = 30 units
      Remaining work = 80 – 30 = 50 units
      Time taken by 'M' alone to complete the remaining work = 50 ÷ 2 = 25 days

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