Question
‘A’ can do a piece of work in 12 days. ‘B’ can
do 60% of the same work in 18 days. If they work together for the entire time and get paid Rs.1540, then find the share of ‘A’.Solution
Let the total work be 36 units. (LCM of 12 and 18) Efficiency of A = 36/12 = 3 units/day Efficiency of B = (36/18) × (60/100) = 6/5 units/day Ratio of the efficiency of A : B = 3 : 6/5 = 15:6 Share of A = (15/21) × 1540 = Rs.1100
I. 3p² - 17p + 22 = 0
II. 5q² - 21q + 22 = 0
I. 3x2 – 17x + 10 = 0
II. y2 – 17y + 52 = 0
I. 35 y² + 58 y + 24 = 0
II. 21 x² + 37 x + 12 = 0
I. 5x2 – 7x – 6 =0
II. 2y2 – 5y – 7 =0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 37x² - 172x + 135 = 0
Equation 2: 29y² - 132y + ...
I: x2 + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. 14p2 – 135p + 81 = 0
II. 7q2 – 65q + 18 = 0
I. 64x2 - 64x + 15 = 0
II. 21y2 - 13y + 2 =0
I. 6y2 – 23y + 20 = 0
II. 4x2 – 24 x + 35 = 0
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