Question
Jatin can complete 20% of work in 5 days. Ankit takes 5
days more than Jatin to complete the work. Ramesh is 20% more efficient than Ankit. Jatin and Ankit started the work together and joined by Ramesh on every third day. They worked this way for 7.5 days and then Jatin and Ramesh left the work. Find the time taken by Ankit to complete the remaining work alone.Solution
Time taken by Jatin to complete the work = 5/0.2 = 25 days Time taken by Ankit to complete the work = (25 + 5) = 30 days Time taken by Ramesh to complete the work = 30/1.2 = 25 days Let the total work = 150 units Efficiency of Jatin = 150/25 = 6 units/day Efficiency of Ankit = 150/30 = 5 units/day Efficiency of Ramesh = 150/25 = 6 units/day Work done by Jatin, Ankit and Ramesh in 3 days = (6 + 5 + 6 + 5 + 6 + 5 + 6) = 39 units Work done by Jatin, Ankit and Ramesh in 7.5 days = 39 × 2 + 6 + 5 + 5.5 = 94.5 units Remaining work = 150 – 94.5 = 55.5 units Required time taken by Ankit = 55.5/5 = 11.1 days
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