Question
16 men can complete a work in 10 days. 10 men started
the same work and left after working for βyβ days. The remaining work is completed by 6 men in 15 days. Find the value of βyβ.Solution
ATQ, Total work = 16 Γ 10 = 160 man-days. When 10 men work for βyβ days, the work done = 10y man-days. Remaining work = 160 - 10y man-days. 6 men complete the remaining work in 15 days, so: 6 Γ 15 = 90 man-days. Therefore, 10y + 90 = 160 10y = 70 y = 70/10 y = 7
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