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ATQ, Total work = 16 × 10 = 160 man-days. When 10 men work for ‘y’ days, the work done = 10y man-days. Remaining work = 160 - 10y man-days. 6 men complete the remaining work in 15 days, so: 6 × 15 = 90 man-days. Therefore, 10y + 90 = 160 10y = 70 y = 70/10 y = 7
If √3 tan 2θ – 3 = 0, then find the value of tanθ secθ – cosθ where 0 < θ < 90°
If (5sinx - cosx) = 2√2sinx, then find the value of 'tanx'
In a right triangle ABC, angle B = 90°. If tan A = 3/4 and the length of the hypotenuse is 25 cm, find the area of the triangle.
If cosec (2A + B) = (2/√3) and cosec (A + B) = √2, find the value of (4A - B) .
If tan θ + cot θ = 5, find the value of tan²θ + cot²θ.
Find the value of: (Sin2 60 ° X cos 30 ° X sec 60°)/tan 30°