Question
A takes 24 hours more than B to complete the work, and
32 hours more than C to complete the same work. The combined time taken by A and B to finish the work is equal to the time taken by C alone. Find the time required by B alone to complete the work.Solution
ATQ,
Let the time taken by C alone to complete the work be ‘x’ days. So, time taken by A alone to complete the work = (x + 32) days. Time taken by B alone to complete the work = (x + 32 – 24)= (x + 8) days According to question, {(x + 32) (x + 8)}/ {(x + 32) + (x + 8)} = x x ² + 40x + 256 = x(2x + 40) x ² = 256 x = 16 So, time taken by B alone to complete the work = 16 + 8 = 24 days
?% of (112.31 ÷ 13.97 × 90.011) = 359.98
40.22 of 249.98% + 459.99 ÷ 23.18 = ?
456.9 + 328.10 - 122.98 = ? + 232.11
108.31% of (4.9/9.012) of ? = 23.9% of 2499.9
A man lost one-fourth of his initial amount in the gambling after playing three rounds. The rule of Gambling is that if he wins he will receive Rs. 1000...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(32.18% of 2399.89 - √624 × 26.25) % of 149.79 = ?
1299.99 ÷ 20.21 = ? + 325.985 - (180 ÷ 6 × 24.03)
256.12 ÷ 7.92 + 26.11 × 7.82 – 44.09 = ?2