Question
A takes 24 hours more than B to complete the work, and
32 hours more than C to complete the same work. The combined time taken by A and B to finish the work is equal to the time taken by C alone. Find the time required by B alone to complete the work.Solution
ATQ,
Let the time taken by C alone to complete the work be ‘x’ days. So, time taken by A alone to complete the work = (x + 32) days. Time taken by B alone to complete the work = (x + 32 – 24)= (x + 8) days According to question, {(x + 32) (x + 8)}/ {(x + 32) + (x + 8)} = x x ² + 40x + 256 = x(2x + 40) x ² = 256 x = 16 So, time taken by B alone to complete the work = 16 + 8 = 24 daysÂ
17 32 99 ? 1965 11784
...77 ? 190 257 331 412
...Given below are three numbers series I, II and II where each series contains a wrong (odd one out) term. The wrong number in series I, II and III are '...
91   93   97   100   ?   113
12 Â Â Â 11 Â Â Â Â 21 Â Â Â Â 62 Â Â Â Â ? Â Â Â Â Â 1234
13 15 ? 63 143 293
...102     153      306      765       ?     8032.5
...17 ? 33 44 57 72
...3 5 7 25 85 481
...1 4 13 46 ? 976
...
Relevant for Exams:
